Superposition principle states that if a single excitation is broken down into few constitutive components, total response is the sum of the responses to individual components. The use of the principle can be illustrated on the following electrostatic example.
Sphere of radius with an empty, spherical cavity of a radius
, has a positive volume charge density
The center of the cavity is at the distance
from the center of the charged sphere (Figure 1).
Figure 1 - Positively charged sphere with an off-centered cavity
According to the superposition principle, total field inside the cavity can be found by adding up individual fields of:
Figure 2 - Representation of an empty volume by a superposition of two opposite charge density domains
Field of any isolated, uniformly charged sphere in its interior at a distance r, can be calculated from Gauss’ Law:
Which yields for a positive sphere:
And for a negative sphere:
Where vectors and
are as defined in Figure 3.
Figure 3 - Relationship between the individual Electric field directions and the vector representing the cavity offset
Therefore, the total electric field in the cavity can be computed as:
From the last equation, it can be concluded that the electric field in the cavity is constant with a direction and that its magnitude (for
and
) is
The field magnitude depends only on the value of the charge density and the distance by which the center of the cavity is offset from the center of the sphere.
In EMS, electromagnetic analysis requires modeling of the surrounding air regions, because very often, significant part of the electromagnetic field extends outside the parts of the simulated system. Once Solidworks part representing the air domain has been imported in the assembly, all the parts should be subtracted from it. To do so:
Figure 4 - 3D model of sphere with a spherical cavity together with surrounding air domain
The simulation is performed as the EMS Electrostatic study . Air is used as a material for all parts.
(To see how to assign materials, see the “Computing capacitance of a multi-material capacitor” example).
To simulate the electric field, a Charge density boundary condition should be assigned to the large sphere, and a Fixed voltage boundary condition should be assigned to the face of the Air region.
To assign a charge density to the Charged sphere:
To see how to assign 0 Volt to the face of the Air region, see “Force in a capacitor” example.
To display the variation of the electric field along the axis that connects the center of the Charged sphere and the center of the cavity:
In the obtained curve (Figure 5), it’s clear that the electric field in the cavity is constant, and its value is , which closely matches the theoretical result. The field in Figure 5 steadily increases with the radius until it meets the cavity
and then remains unchanged through the cavity (till
). The field peaks at the surface of the sphere (
) and then it drops with the square of radius.
[1] http://jkwiens.com/2007/10/24/answer-electric-field-of-a-nonconducting-sphere-with-a-spherical-cavity/